Originally Posted by

**elieh** Hey guys,

Question: A mass of 2.6 kg is maintained in equilibrium in a vertical plane by forces of 5P N and 12P N (where P is an unknown constant) which are perpendicular.

5P is at an angle $\displaystyle \alpha $ from the vertical.

Find the value of $\displaystyle \alpha $ and the value of the constant P.

So 12p is at an angle of $\displaystyle 90-\alpha $ from the vertical. (My reasoning)

Resolving vertically I get: $\displaystyle 5p\cos \alpha + 12p\sin \alpha =26$

And horizontally: $\displaystyle 12p\cos \alpha = 5p\sin \alpha $

After that I'm stuck, simultaneous equations I presume.