tension/polar co ordinates
A particle P of mass m is suspended from a fixed point O by a light inextensible string of length a. The particle is subject to uniform gravity and moves in a vertical plane through O with the string taut
Assuming the standard expression for the components of acceleration in polar coordinates, show from rst principles that
((d^ϴ)/dt^2) +(g/a)sinϴ=0
where where ϴ is the angle between the string and the downwards vertical, and g is the acceleration due to gravity. Give an expression for the tension in the string.
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ok so i thought maybe write about acceleration is in polar co-ordinates and postion but that wasnt smart because obviously they wont sum to one
maybe solve the second order diff but wouldnt i need (g/a)sinϴ in terms of t?
maybe take the (g/a)sinϴ over and intergrate but sides
so i got v=ϴ dot= (gt/a)cosϴ
and x =ϴ=(gt^2)sinϴ
but i actually dont have a clue how to tackle this......