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Math Help - physics:circular motion

  1. #1
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    physics:circular motion

    the space shuttleee is moving in a circular orbit with a speed of 7.8 km/s and a period of 87 minutes.suppose to the direction of motion.the engine porvides a decelaration of 6 m/s^2 that is constant in madnitude and direction.What is the total accelaration of the shuttle?
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by alderon View Post
    the space shuttleee is moving in a circular orbit with a speed of 7.8 km/s and a period of 87 minutes.suppose to the direction of motion.the engine porvides a decelaration of 6 m/s^2 that is constant in madnitude and direction.What is the total accelaration of the shuttle?
    The shuttle acceleration has two components one normal to its direction of
    travell equal to v \dot{\theta} where v is in metres per secons, and \dot{\theta} is in radians per second.
    The other in the direction of travel equal to 6~ \rm{m/s^2}.

    So the magnitude of the accelleration is:

    <br />
a=\sqrt{(v \dot{\theta})^2+6^2}<br />

    RonL
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