# Thread: physics:circular motion

1. ## physics:circular motion

the space shuttleee is moving in a circular orbit with a speed of 7.8 km/s and a period of 87 minutes.suppose to the direction of motion.the engine porvides a decelaration of 6 m/s^2 that is constant in madnitude and direction.What is the total accelaration of the shuttle?

2. Originally Posted by alderon
the space shuttleee is moving in a circular orbit with a speed of 7.8 km/s and a period of 87 minutes.suppose to the direction of motion.the engine porvides a decelaration of 6 m/s^2 that is constant in madnitude and direction.What is the total accelaration of the shuttle?
The shuttle acceleration has two components one normal to its direction of
travell equal to $v \dot{\theta}$ where $v$ is in metres per secons, and $\dot{\theta}$ is in radians per second.
The other in the direction of travel equal to $6~ \rm{m/s^2}$.

So the magnitude of the accelleration is:

$
a=\sqrt{(v \dot{\theta})^2+6^2}
$

RonL