# physics:circular motion

• Aug 21st 2007, 07:53 PM
alderon
physics:circular motion
the space shuttleee is moving in a circular orbit with a speed of 7.8 km/s and a period of 87 minutes.suppose to the direction of motion.the engine porvides a decelaration of 6 m/s^2 that is constant in madnitude and direction.What is the total accelaration of the shuttle?
• Aug 21st 2007, 09:05 PM
CaptainBlack
Quote:

Originally Posted by alderon
the space shuttleee is moving in a circular orbit with a speed of 7.8 km/s and a period of 87 minutes.suppose to the direction of motion.the engine porvides a decelaration of 6 m/s^2 that is constant in madnitude and direction.What is the total accelaration of the shuttle?

The shuttle acceleration has two components one normal to its direction of
travell equal to $\displaystyle v \dot{\theta}$ where $\displaystyle v$ is in metres per secons, and $\displaystyle \dot{\theta}$ is in radians per second.
The other in the direction of travel equal to $\displaystyle 6~ \rm{m/s^2}$.

So the magnitude of the accelleration is:

$\displaystyle a=\sqrt{(v \dot{\theta})^2+6^2}$

RonL