consider a elevator weighing 3200 lbs. rising with a=4.0 ft/s^2

what is the tension in the supporting cable?

Printable View

- August 21st 2007, 08:45 PMalderonphysics
consider a elevator weighing 3200 lbs. rising with a=4.0 ft/s^2

what is the tension in the supporting cable? - August 21st 2007, 09:58 PMCaptainBlack
The net force on the elevator is 3200x4 Newtons. This comprises the sum of

a downward force due to gravity of 3200xg, and the upward force equal to

the tension in the cables, so:

3200x4 = T-3200xg,

so:

T = 3200(4 + g).

**Opps.. lbs not kg, so the elevator mass is ~3200*.4536 ~=1451.5 kg**

**and ft/s not m/s, so ~4 ft/s 4*0.3048 ~=1.22 m/s**

**so we have:**

**T= 1451.5(1.22+g)~=16010 Newtons.**

I would recomend to your instructor that they stop using customary units immeadiatly

the confusion in the system between the units of mass/weight at the very risky and

confusing.

RonL - August 21st 2007, 11:18 PMticbol
If the elevator is going up, the tensile force on the cable must be greater than the weight of the elevator. Then this upward net force is causing the elevator to accelerate upwards. This upward net force is equal to the (mass of the elevator)*(acceleration). Or, the old reliable F = ma.

Weight of elevator = 3200 lbs.

So mass of elevator = 3200/32 = 100 slugs -----if g = 32 ft/sec/sec

F = ma

T -3200 = 100(4)

T = 400 +3200

T = 3600 lbs -----------answer.