1. ## [SOLVED] Help pls/

Hey!!

I'm in a sorta advanced class, but I really can'tt figure out math... always been my weakness.. anyway, the teacher gave us some review questons gor a test nxt week, i was wondering if you can help me w/ them?? Pls. show me how to answer them so i can review it and see where i went wrong, thx! this forum is cool

There are 72 litres of water in water tanks, A, B and C. Comparing the quantity of water in each water tank, A has 8 litres more than twice of B and B has 2 litres less than twice of C. How many litres of water are there in each tank?

There are two men. While the first covers 8 steps, the second covers 5 steps. The first covers a distance by 6 steps and the son covers the same distance by 6 steps. If the second person covers 60 m, how many meters will the father cover?

2. Originally Posted by Cloud9Dub
There are 72 litres of water in water tanks, A, B and C. Comparing the quantity of water in each water tank, A has 8 litres more than twice of B and B has 2 litres less than twice of C. How many litres of water are there in each tank?
Let x be the quantitiy of water in C. Then the volume in B is 2x - 2. The volume in A is then 2(2x - 2) + 8. Since the total volume is 72 L, we know that
$\displaystyle 72 = [2(2x - 2) + 8] + [2x - 2] + [x]$

Solve for x.

-Dan

3. Originally Posted by Cloud9Dub
There are two men. While the first covers 8 steps, the second covers 5 steps. The first covers a distance by 6 steps and the son covers the same distance by 6 steps. If the second person covers 60 m, how many meters will the father cover?
If they both walk the same distance then they both cover 60 m.

Or are they both walking the same number of steps? And why is the son even mentioned since he plays no role in the problem?

This question is a mess.

-Dan

4. It is suggested that the father is the first man and the son is the second. Since "the first covers a distance by 6 steps and the son covers the same distance by 6 steps", their steps are of equal length, but father steps "faster". If the son covers 60 m, the father will cover $\displaystyle \frac{8}{5}60=96$ m.

5. Hello, Cloud9Dub!

I agree with Ivan . . .
. . and the second problem is worded carelessly.

(1) A father and son both cover a certain distance in 6 steps.
(2) The father covers 8 steps in the time his son covers 5 steps.
If the son covers 60 m, how many meters will the father cover?

Statement (1) tells us that their steps have the same length.

Statement (2) tells us that the father walks $\displaystyle \frac{8}{5}$ as fast as his son.
. . His distance will be $\displaystyle \frac{8}{5}$ his son's distance.

Therefore, the father walked: .$\displaystyle \frac{8}{5}\cdot60 \:=\:96$ m.