First read the LaTeX Tutorial
3) To get the domain of you gotta set two things: can't be zero nor negative, then you have to set
The rest are similar.
ok, I've got a couple and instead of splitting them into seperate threads, I thought I would post it all here, ok:
1: (simplify with only positive exponents)
sqrt(4x-16) / 4thsqrt (x-4)^3
and I can only make it 2(square root of (x-4))times(4th square root of (x-4) / x-4
is that right?
2: [(1/x^-2) + (4/x^-1*y^-1) + (1/y^-2)]^(-1/2)
I got square root of (x^2 + 4xy + y^2)/x^2 + 4xy + y^2
is that right?
3: find domain: y=log(2x-12)
is it all real numbers?
4: same deal, y=square root of tanx
all real numbers?
5: y=sqrt (square root) of (x-3) - sqrt(x+3)
all real numbers?
6: (solve albsolute value inequalities)
abs(x+1) < & = abs(x-3)
is is 2 <&= x <&= -4?
7: solve and sign chart:
2x^2 + 4x <&= 3
is it x= .581, 2.581?
8: use synthetic division to factor P(x) then solve P(x)=0
I've tried all numbers and can't get it to work
P(x) = x^3 - 6x^2 + 3x - 10
9: find vertical and horizontal asymptotes
y= (x+4)/(x^2 - 1)
and
y= (x^2 - x - 6) / (x^3 - x^2 + x - 6)
please please please help! I need it by tomorrow morning, so as soon as possible would be unbelievably helpful
THANK YOU!
-meg-
(you don't have to know all of them either, just please I'll take anything, I'm kinda desperare at this point)
also, I work backwards, giving me the answer will do, i can figure it out myself, in fact, I'd probably learn it better if i figured it out by myself, I just need input
First read the LaTeX Tutorial
3) To get the domain of you gotta set two things: can't be zero nor negative, then you have to set
The rest are similar.
Are you sure that isn't ?.8: use synthetic division to factor P(x) then solve P(x)=0
I've tried all numbers and can't get it to work
The other one doesn't factor very nicely and has two non real solutions.
Asymptotes are easy if you just know some rules. To find the vertical asymptotes, find what x value(s) makes the denominator equal 0.9: find vertical and horizontal asymptotes
and
To find the horizontal asymptotes, if the power of the numerator is less than the power of the denominator the x-axis is the horizontal asymptote.
to #4:
. That means which is only possible if with
to #5:
I assume that you mean:
The domain of is
The domain of is
But because the radicand is allways negative that means the domain is the empty set.
= + = + = + = + = + = + = + = + = + = + = + = + = + = + = + = + = + = +
If you mean:
then the domain is:
Translate your inequality: "The graph of the left function should be below the graph of the right function." (see attachment)
Since
and
your inequality becomes:
Solve for x and you'll get:
. That means the solution is the set of x with x < 1.
I've attached a sketch of the 2 functions. On the x-axis I've marked the x values which make the inequality true.