I need to work out the required value of a parallel shunt resistor to shunt a meter.
I have been given the maximum incoming current of 200A (I), the resistance of the meter (Rm) which is 0.1 Ohm and been told that the maximum the meter can read is 1mA (Im).
I've gone down this route:
Voltage = I x Rm = 200 x 0.1 = 20V
Then worked out the current that the meter is pulling = 20V/Rm = 200A
Correct me if i'm wrong, but doesn't that mean that the shunt resistor (Rs) is effectively 0? So the shunt current (Is) be 20/0 = 20A?
Any pointers would be appreciated.