someone used photobucket and now we dont have the pic anymore

2. just remember that

$
x^{-1}
$

means

$
\frac{1}{x}
$

so that is how the
$
b^{-3}
$

gets down to the bottom of the fraction

3. Originally Posted by CONFUSED_ONE

$\left( \frac{ab^{-1}}{2} \right)^3$
Open parantheses (remember to raise each one to that power)
Thus,
$\frac{a^3b^{-3}}{8}$
Remember the rule of negative exponents,
$\frac{a^3}{8} \frac{1}{b^3}=\frac{a^3}{8b^3}$
Q.E.D.

4. oh. so you bring down the b..ohh oikay i get it. thanks for the hlep you two!

5. Welcome

6. Originally Posted by CONFUSED_ONE

how would you simplify that?
Hello,

as you've seen ThePerfectHacker's answer was

$\frac{a^3}{8b^3}$

and that answer you can condense to: $\frac{a^3}{8b^3}= \left( \frac{a}{2b} \right)^3$

Bye