someone used photobucket and now we dont have the pic anymore
$\displaystyle \left( \frac{ab^{-1}}{2} \right)^3$Originally Posted by CONFUSED_ONE
Open parantheses (remember to raise each one to that power)
Thus,
$\displaystyle \frac{a^3b^{-3}}{8}$
Remember the rule of negative exponents,
$\displaystyle \frac{a^3}{8} \frac{1}{b^3}=\frac{a^3}{8b^3}$
Q.E.D.
Hello,Originally Posted by CONFUSED_ONE
as you've seen ThePerfectHacker's answer was
$\displaystyle \frac{a^3}{8b^3}$
and that answer you can condense to: $\displaystyle \frac{a^3}{8b^3}= \left( \frac{a}{2b} \right)^3$
Bye