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Math Help - Please help me simplify

  1. #1
    Junior Member CONFUSED_ONE's Avatar
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    Please help me simplify

    someone used photobucket and now we dont have the pic anymore
    Last edited by MathGuru; October 1st 2006 at 06:43 PM.
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  2. #2
    Member jacs's Avatar
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    just remember that

    <br />
x^{-1}<br />

    means

    <br />
\frac{1}{x}<br />

    so that is how the
    <br />
b^{-3}<br />
    gets down to the bottom of the fraction
    Attached Thumbnails Attached Thumbnails Please help me simplify-indices.jpg  
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  3. #3
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    Quote Originally Posted by CONFUSED_ONE



    \left( \frac{ab^{-1}}{2} \right)^3
    Open parantheses (remember to raise each one to that power)
    Thus,
    \frac{a^3b^{-3}}{8}
    Remember the rule of negative exponents,
    \frac{a^3}{8} \frac{1}{b^3}=\frac{a^3}{8b^3}
    Q.E.D.
    Last edited by MathGuru; October 1st 2006 at 06:44 PM.
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  4. #4
    Junior Member CONFUSED_ONE's Avatar
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    oh. so you bring down the b..ohh oikay i get it. thanks for the hlep you two!
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  5. #5
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    Welcome
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  6. #6
    Super Member
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    Quote Originally Posted by CONFUSED_ONE


    how would you simplify that?
    Hello,

    as you've seen ThePerfectHacker's answer was

    \frac{a^3}{8b^3}

    and that answer you can condense to: \frac{a^3}{8b^3}= \left( \frac{a}{2b} \right)^3

    Bye
    Last edited by MathGuru; October 1st 2006 at 06:44 PM.
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