Results 1 to 4 of 4

Math Help - find R_AB

  1. #1
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580

    Cool find R_AB

    find R_{ab}

    first I added 5\Omega + 5\Omega = 10\Omega

    then \frac{10\Omega\times10\Omega}{10\Omega+10\Omega}=5  \Omega

    then \frac{8\Omega\times8\Omega}{8\Omega+8\Omega}=4\Ome  ga

    so 4\Omega+ 5\Omega+ 1\Omega = \boxed{1\Omega}

    any not really sure about this
    Attached Thumbnails Attached Thumbnails find R_AB-q1.1.png  
    Follow Math Help Forum on Facebook and Google+

  2. #2
    A Plied Mathematician
    Joined
    Jun 2010
    From
    CT, USA
    Posts
    6,318
    Thanks
    4
    Awards
    2
    I'm not sure, either. It should be

    4\Omega+ 5\Omega+ 1\Omega = \boxed{10\Omega}.

    Everything else looks ok, though.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580
    sorry typo

    but haven't learned how to add or subtract numbers yet...

    more to come
    Follow Math Help Forum on Facebook and Google+

  4. #4
    A Plied Mathematician
    Joined
    Jun 2010
    From
    CT, USA
    Posts
    6,318
    Thanks
    4
    Awards
    2
    Quote Originally Posted by bigwave View Post
    more to come
    Oh, goodie!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 8
    Last Post: March 22nd 2011, 04:57 PM
  2. Replies: 2
    Last Post: July 5th 2010, 08:48 PM
  3. Replies: 1
    Last Post: February 17th 2010, 03:58 PM
  4. Replies: 0
    Last Post: June 16th 2009, 12:43 PM
  5. Replies: 2
    Last Post: April 6th 2009, 08:57 PM

Search Tags


/mathhelpforum @mathhelpforum