distance problem

**carlasader** · July 15th 2007, 11:27 AM

very hard stuff ..need help please

**janvdl** · July 15th 2007, 12:26 PM

b) $v^2 = u^2 + 2as$
$1296 = + (2)(2)(s)$
$s = 324$

$s = ut + \frac{1}{2} a t^2$
$s = ut \ (There \ was \ no \ acceleration)$
$s = (36)(90)$
$s = 3240$

$v^2 = u^2 + 2as$
$0 = 36^2 + (2)(-3)(s)$
$s = 216$

Add all those distances together and you get: 3780 metres

**janvdl** · July 15th 2007, 12:27 PM

c) T2 takes 150s to complete the journey.
I calculated T1 to take only 118s.

But they travelled the same distance and route. Im guessing that Train 1 was therefore faster. Maybe it had a bigger average speed.

d) For T2
s = 3870
t = 150
u = 0
v = 0
a = ?

$s = ut + \frac{1}{2} a t^2$
$3870 = \frac{1}{2} a 150^2$
$a = \frac{43}{125}$

$v = u + at$
$v = 0 + \frac{43}{125} (150)$
$v = 51,6 ms^-1$

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