As you can see here, it looks like completing the square in the denominator, followed by a trig substitution, will conquer your integral. Click Show Steps to see how WolframAlpha does it.
The problem is stated as follows: The acceleration of a rocket travelling upward is given by , where s is in meters. Determine the time needed for the rocket to reach an altitude of s=100m. Initially, v=0, s=0, t=0.
Then, we have:
and it is at this point my mind draws a blank.... I am taking this course at the same time as integral calculus math is being tought to me, and so I really have not much to go off of for this. Any suggestions?
As you can see here, it looks like completing the square in the denominator, followed by a trig substitution, will conquer your integral. Click Show Steps to see how WolframAlpha does it.
Hmm. Well, here's another way to solve your problem: view it as a standard, second-order differential equation (which is what it is, of course). But that's probably even more advanced than the trig substitution, etc. Take a look at this wiki page for trig substitutions, and take a look here around Post # 12 for substitutions in general.