when batteries are connected in series the total internal resistance of the batteries can be taken as 3(0.5) so with that and the additional 6, you'll get 7.5
1. The problem statement, all variables and given/known data
i am wondering if this is correct. this is the question;
Three cells, each of e.m.f. 1·5 V and internal resistance 0·50 Ω, are connected in series to
make a battery of e.m.f. 4·5V. The battery is connected to a resistor, R, of resistance 6·0 Ω.
2. Relevant equations
3. The attempt at a solution
TOTAL VOLTAGE = 4.5V
TOTAL RESISTANCE = 6.5 OHMS
but the answer states the total resistnace is 7.5 ohms.
can someone kindly explain how?