# Logarithm Question

• January 17th 2006, 06:51 PM
Numbnut247
Logarithm Question
hey guys i need help on a question:
If log 5 = m and log 7 = n, find log (35/10) in terms of m and n.

Thanks
• January 17th 2006, 07:24 PM
ThePerfectHacker
Quote:

Originally Posted by Numbnut247
hey guys i need help on a question:
If log 5 = m and log 7 = n, find log (35/10) in terms of m and n.

Thanks

You probably mean that $\log 2=m$?
Then
$\log (35/10)=\log (7/2)=\log 7-\log 2=n-m$.
Q.E.D.
• January 18th 2006, 10:39 AM
SkyWatcher
an other solution
Quote:

Originally Posted by Numbnut247
hey guys i need help on a question:
If log 5 = m and log 7 = n, find log (35/10) in terms of m and n.

Thanks

if you had the algebric equation log((a*b)/c)=log(a)+log(b)-log(c)
and if log (10)=1
Then the awnser to your question would be m+ n-1
But i always mix up whith all those formula
check it whith a calculus machine if youve got one!

by!