Q 1 :

Two masses 5 kg and 10 kg are suspended from ends of a string (mass less inelastic )

passing over a smooth pulley . Calculate the acceleration of the masses

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This is the first body acting by two force on is T other is gravity

Now we write the equation

m1g T = m1a

( I write m1g ) because T < than m1g )

Now the second body

T - m2g = m2a

( I write - m2g because T > than gravity )

Now I add both equations

m1g T = m1a

T - m2g = m2a

>

,,,m1g- m2g=m1a+m2a

a = (m1 m 2)/ ( m1 + m 2 ) X g

= - 735.75

To find T

m1g T = m1a

5 X 9.81 T = 5 (- 735.75 )

49.05 T = -3678.78

-T = -3678.78 - 49.05

T = 3727.8