# Math Help - Indices

1. ## Indices

You are given that n= 2^2 * 5

Write 40n as the product of its prime factors.

2. $40=2^3\cdot 5$.
Then $40n=2^3\cdot 5\cdot 2^2\cdot5=2^5\cdot 5^2$

3. Originally Posted by GAdams
You are given that n= 2^2 * 5

Write 40n as the product of its prime factors.
$n = 2^2 \cdot 5$

$\Rightarrow 40n = 40 \cdot 2^2 \cdot 5$

$= 8 \cdot 5 \cdot 2^2 \cdot 5$

$= 2^3 \cdot 5 \cdot 2^2 \cdot 5$

$= 2^5 \cdot 5^2$

EDIT: Why am i always the second one to post today?