You are given that n= 2^2 * 5

Write 40n as the product of its prime factors.

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- Jul 6th 2007, 12:07 PMGAdamsIndices
You are given that n= 2^2 * 5

Write 40n as the product of its prime factors. - Jul 6th 2007, 12:11 PMred_dog
$\displaystyle 40=2^3\cdot 5$.

Then $\displaystyle 40n=2^3\cdot 5\cdot 2^2\cdot5=2^5\cdot 5^2$ - Jul 6th 2007, 12:12 PMJhevon