# Indices

• July 6th 2007, 12:07 PM
Indices
You are given that n= 2^2 * 5

Write 40n as the product of its prime factors.
• July 6th 2007, 12:11 PM
red_dog
$40=2^3\cdot 5$.
Then $40n=2^3\cdot 5\cdot 2^2\cdot5=2^5\cdot 5^2$
• July 6th 2007, 12:12 PM
Jhevon
Quote:

You are given that n= 2^2 * 5

Write 40n as the product of its prime factors.

$n = 2^2 \cdot 5$

$\Rightarrow 40n = 40 \cdot 2^2 \cdot 5$

$= 8 \cdot 5 \cdot 2^2 \cdot 5$

$= 2^3 \cdot 5 \cdot 2^2 \cdot 5$

$= 2^5 \cdot 5^2$

EDIT: Why am i always the second one to post today?