I am very unsure about how to tackle this problem.

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- Jul 2nd 2007, 11:31 AMGAdamsExpressions
I am very unsure about how to tackle this problem.

- Jul 2nd 2007, 11:36 AMjanvdl
The 2nd and 6th boxes are right i think.

Becos they have $\displaystyle something^3 $ - Jul 2nd 2007, 01:16 PMCaptainBlack
- Jul 2nd 2007, 01:18 PMjanvdl
Why Captain? Because it's a side multiplied by a side squared?

Hmm, didn't see that one. - Jul 2nd 2007, 01:25 PMJhevon
- Jul 2nd 2007, 07:38 PMCaptainBlack
- Jul 3rd 2007, 02:44 AMtopsquark
Of course, any of them can have "hidden" units, where the constant (such as the $\displaystyle \pi$) carries a unit with it...

-Dan