Results 1 to 7 of 7

Math Help - Upper and Lower bounds

  1. #1
    Senior Member
    Joined
    Apr 2006
    Posts
    290

    Upper and Lower bounds

    Hi, i would just need someone to explain to me how to do this question in a very straight forward easy way.

    The volume of oil in a tank is 1000 litres, correct to the nearest 10 litres. The oil is poured into tins of volume 2.5 litres, correct to one decimal place.

    Calculate the upper bound of the number of tins which will be required?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    12,041
    Thanks
    885
    Quote Originally Posted by Natasha1 View Post
    Hi, i would just need someone to explain to me how to do this question in a very straight forward easy way.

    The volume of oil in a tank is 1000 litres, correct to the nearest 10 litres. The oil is poured into tins of volume 2.5 litres, correct to one decimal place.

    Calculate the upper bound of the number of tins which will be required?
    \displaystyle \frac{990}{2.6} < n < \frac{1010}{2.4}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member
    Joined
    Apr 2006
    Posts
    290
    Thanks. Is the answer to the question Calculate the upper bound of the number of tins which will be required? just n < 1010 / 2.4
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Dec 2009
    Posts
    3,120
    Thanks
    1
    Quote Originally Posted by Natasha1 View Post
    Thanks. Is the answer to the question Calculate the upper bound of the number of tins which will be required? just n < 1010 / 2.4
    Yes, the maximum possible amount of oil divided by the minimum amount per tin of 2.4 litres gives the max number of tins.
    That will cause the maximum amount of tins to be required.
    You will have to round up to the nearest whole number of tins to contain all the oil.
    Last edited by Archie Meade; November 21st 2010 at 06:14 AM.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Senior Member
    Joined
    Apr 2006
    Posts
    290
    Yes but to the nearest 10 surely 1000's upper bound is 1004.9999999999999 as soon as it's 1005 it rounds to 1005. So why is it not 1005 divided by 2.4?
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor Unknown008's Avatar
    Joined
    May 2010
    From
    Mauritius
    Posts
    1,260
    Correct, only that if it's 1005, it'll be rounded to 1010.

    EDIT: Didn't read the initial question well, corrected now.
    Last edited by Unknown008; November 21st 2010 at 06:23 AM.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    MHF Contributor
    Joined
    Dec 2009
    Posts
    3,120
    Thanks
    1
    Quote Originally Posted by Natasha1 View Post
    Yes but to the nearest 10 surely 1000's upper bound is 1004.9999999999999 as soon as it's 1005 it rounds to 1005. So why is it not 1005 divided by 2.4?
    Yes, if 1000 is the result after rounding to the nearest 10, then a value from above 995
    to below 1005 has been approximated as 1000.

    So divide 1005 by 2.4 will give a maximum value,
    the result of which needs to be rounded up to the next natural number
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Upper and lower bounds
    Posted in the Algebra Forum
    Replies: 3
    Last Post: March 25th 2011, 04:36 AM
  2. Upper and Lower Bounds
    Posted in the Algebra Forum
    Replies: 5
    Last Post: March 11th 2010, 11:44 AM
  3. Upper and lower bounds help?
    Posted in the Algebra Forum
    Replies: 1
    Last Post: February 5th 2010, 02:07 PM
  4. Upper and Lower Bounds
    Posted in the Algebra Forum
    Replies: 1
    Last Post: August 31st 2009, 06:52 PM
  5. Greatest lower bounds and least upper bounds
    Posted in the Calculus Forum
    Replies: 3
    Last Post: March 31st 2008, 07:31 PM

Search Tags


/mathhelpforum @mathhelpforum