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Math Help - Variable conditions of double slit interference

  1. #1
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    Variable conditions of double slit interference

    Hi
    Can anyone help on this. The questions is as follows:

    In a double slits experiment using red light, a fringe pattern is observed on a screen at a fixed distance from the double slits. How would the finge pattern change if:

    a) The screen is moved closer to the slits
    b)one of the double slits is blocked completely.

    I surmised the following:
    a) The standard formula
    W= (DX Wavelength)/s
    W= Fringe seperation
    D= distance of slit to the screen
    s= distance between centre of the slits
    Since D Represents the distance of the slit from the the screen, it is a proportional relationship to the fringe seperation(W). So, if the distance is decreased less spaced.

    b)I am not sure of this. Blocking one of the double slits seems to imply a reduced wavelength. Red has one of the longest wavelengths. From the above formula, it seems to suggest the same effect as above. But a part of me is suggesting there is an increased wavelength.

    Please!!!
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  2. #2
    MHF Contributor Unknown008's Avatar
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    a) The formula can be written as

    sW = D\lambda

    Keeping s, and lambda constant, as D decreases, W decreases, correct.

    b) When you have only one diffraction, there is no more interference and the resultant is a single slit diffraction pattern.
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  3. #3
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    Quote Originally Posted by Unknown008 View Post
    a) The formula can be written as

    sW = D\lambda

    Keeping s, and lambda constant, as D decreases, W decreases, correct.

    b) When you have only one diffraction, there is no more interference and the resultant is a single slit diffraction pattern.
    Thanks a lot
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