thank you CaptainBlack help me how latex and prove $\displaystyle \sqrt{1+2\sqrt{1+3\sqrt{1+4\sqrt{1+...}}}} = 3$
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Originally Posted by perash thank you CaptainBlack help me how latex and prove $\displaystyle \sqrt{1+2\sqrt{1+3\sqrt{1+4\sqrt{1+...}}}} = 3$ we use [tex] [ /math] here
Originally Posted by perash thank you CaptainBlack help me how latex and prove $\displaystyle \sqrt{1+2\sqrt{1+3\sqrt{1+4\sqrt{1+...}}}} = 3$ $\displaystyle \sqrt{1+2\sqrt{1+3\sqrt{1+4\sqrt{1+...}}}} = 3 $
It never becomes 3. It only tends to become 3.
Originally Posted by perash thank you CaptainBlack help me how latex and prove $\displaystyle \sqrt{1+2\sqrt{1+3\sqrt{1+4\sqrt{1+...}}}} = 3$ Try this link it should give you some ideas. the proof isn't full, but maybe you can pick up the slack using induction or something to prove any claim you make
Originally Posted by Jhevon Try this link it should give you some ideas. the proof isn't full, but maybe you can pick up the slack using induction or something to prove any claim you make That's a fascinating expansion. -Dan
Originally Posted by topsquark That's a fascinating expansion. -Dan it is, isn't it?! It's so simple to understand, but i never would have thought about doing that in a million years
Originally Posted by topsquark That's a fascinating expansion. Originally Posted by Jhevon it is, isn't it?! It's so simple to understand, but i never would have thought about doing that in a million years The poster on the other site who solved this problem claims it belongs to Ramanajuan. If you never read anything of Ramanajuan, be prepared! Ramanajuan does this type of stuff of the all time. He realizes the most crazy manipulations.
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