x.y .z integers such that
Last edited by CaptainBlack; June 25th 2007 at 04:11 AM.
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Originally Posted by perash x.y .z integers such that First put , does that help? RonL
Originally Posted by CaptainBlack First put , does that help? RonL Why "4" Captain? Could you please explain a bit, i'd like to know how to do this too...
Originally Posted by janvdl Why "4" Captain? Could you please explain a bit, i'd like to know how to do this too... Because, I think it is a mistake.
Originally Posted by ThePerfectHacker Because, I think it is a mistake. I dont agree, i dont think we can assume just 1 set of numbers... I might be wrong, but i dont think there can be only one solution...
Originally Posted by janvdl Why "4" Captain? Could you please explain a bit, i'd like to know how to do this too... Because if: and then , and I have a solution in my notebook for . RonL
Originally Posted by perash x.y .z integers such that CB's hint was not a typo. Let's try x = 4: Thus y = 1 and z = 3. Quite clever really. Applying the same logic that gave CaptainBlack x = 4, we can also do x = 5. If there are any more solutions out there I can't find them with this scheme in mind, anyway. -Dan
Hello, perash! This is what CaptainBlack suggested . . . Since . let Then: . Then it's obvious that: . Got it?