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Math Help - 1/4th Life expression for First Order Rxn

  1. #1
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    1/4th Life expression for First Order Rxn

    ln(\frac{[A]_{\circ}}{[A]_{t}})=kt
    ln(\frac{[A]\circ}{\frac{1}{4}[A]_{\circ}})=kt_\frac{1}{4}
    ln(4)=kt_{\frac{1}{4}}
    do I set t=1/4 ?
    \frac{ln(4)*4}{k}
    \frac{5.545}{k}

    What am I doing wrong here? The answer is allegedly 1.386/k

    However, this answer key has been wrong before. Can someone please confirm/deny this?

    Thank you
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  2. #2
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    Quote Originally Posted by Vamz View Post
    ln(\frac{[A]_{\circ}}{[A]_{t}})=kt
    ln(\frac{[A]\circ}{\frac{1}{4}[A]_{\circ}})=kt_\frac{1}{4}
    ln(4)=kt_{\frac{1}{4}}
    do I set t=1/4 ?
    \frac{ln(4)*4}{k}
    \frac{5.545}{k}

    What am I doing wrong here? The answer is allegedly 1.386/k

    However, this answer key has been wrong before. Can someone please confirm/deny this?

    Thank you
    I assume that you want to calculate the value of t (?).

    If so:

    \ln(4)=k \cdot t~\implies~t = \dfrac{\ln(4)}{k} \approx \dfrac{1.38629}{k}
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  3. #3
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    Quote Originally Posted by Vamz View Post
    ln(\frac{[A]_{\circ}}{[A]_{t}})=kt
    ln(\frac{[A]\circ}{\frac{1}{4}[A]_{\circ}})=kt_\frac{1}{4}
    ln(4)=kt_{\frac{1}{4}}
    do I set t=1/4 ?
    No, you don't "set t= 1/4". It is not t that is 1/4. The value of A is 1/4 the value of A_0 which is why you replaced [A] by [A]\circ.
    What does t_{1/4} mean? I assume the "1/4" is a subscript saying "the value of t at which A is 1/4 its original value". If so there is NO "t" in the equation. There is t_{1/4} and that is what you want to solve for.

    \frac{ln(4)*4}{k}
    You have been fooled by your own notation! You have multiplied by 4 as if t_{1/4} meant that t had been multiplied by 1/4.

    \frac{5.545}{k}

    What am I doing wrong here? The answer is allegedly 1.386/k

    However, this answer key has been wrong before. Can someone please confirm/deny this?

    Thank you
    Follow Math Help Forum on Facebook and Google+

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