# Thread: Do I have this right?

1. ## Do I have this right?

Car held in place on ramp by 2 forces. One is 2140N by the brakes, which holds it from rolling down the ramp. The other is a reaction force by the ramp of 9850N, perpendicular to the ramp. This forces keeps the car from going thru the ramp.

What is the weight of the car and what angle with the horizontal is the ramp inclined.

I found the weight as 10080N and theta as 12.26 degree.

Do I have this correct?

2. Yes, it's good. Sorry, I did a calculator mistake...

$\displaystyle mg = \dfrac{9850}{cos(12.26)} = 10080 N$

3. What the hell is wrong with you? Why would you post that. Someone please ban him.

4. Awesome, thanks.
If you use 12.6 degree in stead, you get what my weight is. Thanks to confirm!!!!!!!!

5. What the hell is wrong with you? Why would you post that. Someone please ban him.
What?

6. Originally Posted by Unknown008
What?
don't know what he meant by that ... but I do get mg = 10080 N

7. I'm still getting 10110 N... =/

EDIT: I think... I put in 9880 in my calculator instead of 9850... now, how could this happen thrice in a row?

Thanks for checking... I really don't know how I made this error...

8. Originally Posted by skeeter
don't know what he meant by that ... but I do get mg = 10080 N
lol. Sorry. That was in response to someone who had posted some obscene photos on pretty much every thread he visited as a consequence of not have gotten what he considered a satisfactory answer.

9. Originally Posted by Chris11
lol. Sorry. That was in response to someone who had posted some obscene photos on pretty much every thread he visited as a consequence of not have gotten what he considered a satisfactory answer.
note the small triangular icon on the lower left of each post ... use it to report any improper post to a moderator.