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Math Help - mixing

  1. #1
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    mixing

    1.If 0.5ml of serum is mixed with 1.0ml of water and a glucose test is performed resulting in a reading of 200mg/dl from the instrument, what is the final reported result?

    2.If a 1:5 dilution is made with 0.5 ml of serum, how much water is used?

    3.You are given a series of ten tubes, each of which contain 5ml of diluents. To the first tube is added 1ml of serum, and a serial dilution using 1ml is carried out in the remaining tubes. what is the serum concentration in tubes 4 and 8?
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  2. #2
    dratiffarid
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    Med stuff

    Patient has diabetes mellitus.
    Anything more than 140 mg/dL is considered as diabetes mellitus.
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  3. #3
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    Question yes thats true

    yes that is true but i need to try to work this problem. Thank you very, very much for your reply. It is informativeand is relative, but not the answer needed in this particular problem.
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by labrat View Post
    1.If 0.5ml of serum is mixed with 1.0ml of water and a glucose test is performed resulting in a reading of 200mg/dl from the instrument, what is the final reported result?
    Ummm... 200 mg/dL? Reported result of what, specifically?

    -Dan
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by labrat View Post
    2.If a 1:5 dilution is made with 0.5 ml of serum, how much water is used?
    \frac{1}{5} = \frac{0.5~mL}{x}

    So
    x = 5 \cdot (0.5~mL) = 2.5~mL

    -Dan
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  6. #6
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by labrat View Post
    3.You are given a series of ten tubes, each of which contain 5ml of diluents. To the first tube is added 1ml of serum, and a serial dilution using 1ml is carried out in the remaining tubes. what is the serum concentration in tubes 4 and 8?
    The first tube contains 5 mL of dilutent (solvent?) and 1 mL serum. We take 1 mL of solution from this so we have
    \frac{1}{5} = \frac{x}{1~mL}

    x = 0.2~mL
    we are taking 0.2 mL of serum from tube 1.

    We mix this into 5 mL of dilutent in tube 2. Then take 1 mL of solution from this and put it into tube 3, etc.

    Each time we do this we are reducing the amount of serum by a factor of 5. So the amount of serum s, in each tube t is going to be of the form:
    s_t = (1~\text{mL serum}) \left ( \frac{1}{5} \right ) ^t

    So in tube 4 we have
    s_4 = (1~\text{mL serum}) \left ( \frac{1}{5} \right ) ^4 = 0.0016~mL

    So the concentration in tube 4 is \frac{0.0016~\text{mL serum}}{5~\text{mL dilutent}}

    and in tube 8 we have
    s_8 = (1~\text{mL serum}) \left ( \frac{1}{5} \right ) ^8 = 2.56 x 10^{-6}~mL

    So the concentration in tube 8 is \frac{2.56 x 10^{-6}~\text{mL serum}}{5~\text{mL dilutent}}

    -Dan
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  7. #7
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    Thanks a Bunch

    Thank you so very much. You have been a big help. Im in my first semester of college and struggling.I really appriciate your help so much.
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  8. #8
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by labrat View Post
    Thank you so very much. You have been a big help. Im in my first semester of college and struggling.I really appriciate your help so much.
    No problem! Glad I was able to help.

    -Dan
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