Thread: Need help getting started..

Sled of 196 N is being pulled across a horizontal surface at a constant velocity. So it's in equilibrium right??
The pulling force(Tension force?) has a magnitude of 80 n and is direct at an angle 30degree above the horizontal. Determine the coefficient of the kinetic friction.

I am stuck on drawing the FBD. I suck at those. I get them confused.
Need help on getting started, thanks.

So 30 degree angle from the 0degree, Force of 80 is perpendicular to that, so at 120 degrees?? Where do I put the Ff? to figure out the u

Originally Posted by bradycat

Sled of 196 N is being pulled across a horizontal surface at a constant velocity. So it's in equilibrium right??
The pulling force(Tension force?) has a magnitude of 80 n and is direct at an angle 30degree above the horizontal. Determine the coefficient of the kinetic friction.

I am stuck on drawing the FBD. I suck at those. I get them confused.
Need help on getting started, thanks.

So 30 degree angle from the 0degree, Force of 80 is perpendicular to that, so at 120 degrees?? Where do I put the Ff? to figure out the u

Here is the free body diagram

Ok, so do I solve for Fy and sub that into Fx? What letter do you give the 80N just P for pull or T for tension?
I solve for Fn for Fy and plug that into Fn in Fx?

Thanks for the diagram I was off somewhat for sure.

Solve for eta the normal force in the 2nd equation.

Sub this into the first equation and solve for the coefficient of kinetic friction

OK that is what I meant, I typed it wrong. Thank you. I will study that.