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- Oct 27th 2010, 07:25 AM #1

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- Oct 27th 2010, 07:33 AM #2

- Oct 27th 2010, 08:00 AM #3

- Oct 27th 2010, 08:15 AM #4

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- Oct 27th 2010, 08:21 AM #5
Right. For this one, one way of removing all the fractions is to multiply everything by the least common denominator.

$\displaystyle \dfrac{x}{4}- 1 = \dfrac23 + x$

Multiply by 12;

$\displaystyle 3x- 12 = 8 + 12x$

Now, bring all the x on one side and the rest on the other side. Can you complete it now?

- Oct 27th 2010, 08:29 AM #6

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- Oct 27th 2010, 08:31 AM #7

- Oct 27th 2010, 11:38 AM #8
Thread closed. Forum rule #8: http://www.mathhelpforum.com/math-he...ng-151418.html