Use the fact that the grativational pull provides the centripetal force.
Let m be the mass of the satellite,
r the distance from the Earth's centre,
omega the angular velocity of the satellite,
M the mass of the Earth.
Now, fill in the values that you know.
You should be able to get the value of r, the distance of the satellite from the centre of the Earth and then, the height above the ground.
Of course, there are assumptions made here to make it easier.
Post the answer that you get!
Answer I got: 3.59 x 10^7 m