Thread: Enthalpy using Hess's law (Chem)...

This is the question:


Now, I've gotten as far as this:

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Don't know if it's right or wrong, but solve and post all the steps..

Not all the equations show up... =/

But I suppose that's what are given and this is how I work them out:



You are already given which is -91.8\ kJ/mol. (and this I think is the enthalpy of reaction and not formation and hence, you do not divide by 2)

Then, (since you have 3 mol of water being formed from my Hess Cycle)

Then, (I think they gave you the standard enthalpy of combustion of ammonia. So, for each mol of ammonia burnt, you get 906.2 kJ but since you burn 2 moles, it's twice)

Then, This is what you need to find I think.

Then, from Hess' Law, we find that by following the arrows:



This will give you the answer.