Yes, you'll have centripetal force, but you'll also have gravity (pushes the passenger into the seat; hence, by Newton's 3rd law, the seat pushes back into the passenger). Just add them up to get the total.
While driving along a country lane with a constant speed of 17.0 m/s, you encounter a dip in the road. The dip can be approximated as a circular arc, with a radius of 65.0m. What is the normal force exerted by a car seat on a 80.0kg passenger when the car is at the bottom of the dip.
Do you have to do 2 equations here?? 1 will be centripetal force. Fc=mv^2/r?
The other v=d/t???
I am not quite sure on that one.
Any help to get me started would be great. Or do I have it wrong?