Can someone explain the oxidation selection on calculating electrons as noted
Ok. I am studying my notes and have a question on # of p,f and e.
Atom of Nitrogen-14 = 14 over 7 N p=7 n=7 e=?
net charge/oxdation 2,+-3,4,5
Atom of Iron -256 = 56 over 26 FE p=26 n=30 e??
net charge 2,3
Atom of Uranium-256= 236 over 92 U p=92 n=144 e=
net charge 3,4,5,6
I am to write the nuclide symbol and state the number of p,n,e.
Question I have is how do I know which charge to use to calculate the electrons?
If there is a negative # I use that one, but if it's only positive, which one do I use like in U and Fe??