Yes, that's right. Hooke's law says that the force on a spring is given by the spring constant times the distance the spring is extended: F= kx. So k= F/x or your W/x= 71 N/.71 m= 100 N/m.
A typical compound archery bow requiers a force of 133 N to hold an arrow at "full drwa " ( pulled back 71 cm ). ssunimg that the bow obeys hooke's law . what is its spring constant ?
did conver 71 to m
did use k = W/x to find spring constant ?
plese help me ?
That's the question which should be answered. Nothing more, right?
In other words: You need a force F to extend the spring by a distance d. And you need a constant k which refers to the properties of the individual spring. Hooke's law states then:
With your values:
F = 133 N
d = 0.71 m
you'll get:
And now your question is answered!
What exactly do you want to calculate by that?
I'll include the units into this term and you'll get:
The result has the "unit"
That has definitely nothing to do with a compound bow.
This formula is only valid if a weight pulls at the spring (perpendicularly to the surface of Earth) and extend it.
thank you
I have anothor quetion now I drwa graph between
How do we find k from graph
Are we calculate the slope then finid k
like = 51 - 19 / 0.2 - 0.1 = 32/0.1 but convert 32 to m then 0.032/0.1 = 0.32 but what id here the unit of solpe ?
and now find k = 1/0.032 =3.125 and what is the uint here ?
plese check mu answer is correct and what is the uint of slope and k ?