the angle A is opposite the smaller side of the two given sides of the triangle. Therefore you can't use your congruent laws(?). Depending on the length of a you can get
no triangle (a is too short)
exactly one triangle (then it is a right triangle)
The last case happens here. So it is obvious that you can't determine the value of angle B and you can't determine the shape of the triangle. Therefore the right choice is (4).
I've attached a sketch to prove my statement.
Alrighty, I'm really sorry but I have more questions from the January 2006 Regents Examination that can be found here http://www.nysedregents.org/testing/mathre/b106.pdf
The Answers are found here http://www.nysedregents.org/testing/mathre/bkey106.pdf
On this test, I have problems with numbers 4 (although I guessed it correctly), 9, 15, 16, and 17. Above all, I am completely stymied by number 30 and 31. I would highly appreciate any help that can be given in this direction towards myself. I grant all of you, Good day.
Along with Norman I'm facing some difficulties. I was doing the August 2006 regents i got 4 wrong out of the 20 multiple choice so far. The questions i have is with 11, 13 I got right, but i partially guessed/ 17 i was able to break it down altitle bit but i still got the wrong answer/ for now that is it thanks
MATH B REGENTS IN 2 AND A HALF HOURS
To find the intersections, equate the functions: .11. What is the total number of points of intersection
for the graphs of the equations: and
. . and we get: .
Hence, the only point of intersection is:
. . Answer: .
Since the perimeter is 18, the length of a side is13. If the perimeter of an equilateral triangle is 18,
the length of the altitude of this triangle is:
. .Does this diagram insprire you to find ?Code:* /|\ / | \ / | \6 / |h \ / | \ * - - + - - * 3
17. The expression is equivalent to:
You're expected to know the identity: .
We have: .
. . Answer: .
for , (theorem) angles in a semicircle subtended by the diameter are
and for , (theorem) the angle formed by the radius of a circle and a tangent to the circle at the point of tangency is
Also, since they are alternate interior angles
Consequently, since the angles of a triangle add up to . since we showed that the two triangles have two angles congruent, the third angle must be congruent as well, since the third angle will be 180 - the other two angles, and we would get the same value for each triangle
Thus the two triangles are similar