How many grams of nitric acid ($\displaystyle HNO_3$) will be produced from the reaction of $\displaystyle 8.25 g$ of $\displaystyle NO_2$ and $\displaystyle 2.25 g$ of $\displaystyle H_2O$ in the following unbalanced reaction:

$\displaystyle NO_2(g)$ + $\displaystyle H_2O(l) $ $\displaystyle \rightarrow $ $\displaystyle HNO_3(l)$+$\displaystyle NO(g)$

I balanced it:

$\displaystyle 3NO_2(g)$ + $\displaystyle H_2O(l) $ $\displaystyle \rightarrow $ $\displaystyle 2HNO_3(l)$+$\displaystyle NO(g)$

Also, how much of the excess reagent is remaining?

I haven't done chemistry in a while and am personally not so good at it, but my girlfriend wanted to see if I could get some help for her.