A 3-kg particle has a velocity of (3i - 4j) m/s. Find the magnitude of its momentum.
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Originally Posted by jaycas21 A 3-kg particle has a velocity of (3i - 4j) m/s. Find the magnitude of its momentum. Momentum: $\displaystyle p=mv $ so: $\displaystyle |p| = m|v| = m\sqrt{3^2+4^2}=5m \mbox{ kg.m/s} $ RonL
Yes I got that too but the answer are as follows: 9 kg.m/s -12 kg.m/s 15 kg.m/s 3 kg.m/s
Originally Posted by jaycas21 Yes I got that too but the answer are as follows: 9 kg.m/s -12 kg.m/s 15 kg.m/s 3 kg.m/s If you look carefully at CaptainBlack's work you will see that he simply forgot to multiply by m. His answer is the magnitude of the velocity, so the answer is 3*5 kg m/s = 15 kg m/s. -Dan
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