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- Sep 12th 2010, 07:28 PM #1

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- Sep 12th 2010, 08:10 PM #2

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- Sep 13th 2010, 01:09 PM #3

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- Sep 13th 2010, 01:49 PM #4

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Hello, matgrl!

I'll do this one "from scratch" . . .

Code:A * /|\ / | \ / | \ a / | \ a / |h \ / | \ / | \ B * - - - + - - - * C D a/2

We have equilateral triangle with side

The altitude bisects the base, so

Pythagorus says: .

. . . . . . . . . . . . .

The area of the triangle is: .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Gerbert's formula has: .

. . which is slightly smaller than the true area.

The relative error is: .

. . . . . about 1% as emakarov already stated.

- Sep 13th 2010, 06:10 PM #5

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- Sep 13th 2010, 06:15 PM #6

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- Sep 13th 2010, 08:22 PM #7

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