What is the sum of three smallest prime numbers each of which is two more than a perfect positive cube?
Hello again, Rimas!
Am I reading it wrong?
It is very simple . . .
What is the sum of three smallest prime numbers each of which
is two more than a perfect positive cube?
$\displaystyle \begin{array}{cc} \text{cube} & \text{two more} \\
1^3 = 1 & 3 \\ 2^3 = 8 & \not1\!\!\!\!\not0 \\ 3^3 = 27 & 29 \\ 4^3 = 64 & \not6\!\!\!\not6 \\ 5^3 = 125 & 127 \end{array}$
Therefore: .$\displaystyle 3 + 29 + 127\;=\;157$