What is gained when is computed as (for ) rather than the "direct" (but not naive) way?

You get a smaller base (not sure if that helps, but I'll leave it to be corrected (Giggle)) ... on the other hand, introduces (additional) error.

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- September 3rd 2010, 02:02 AMcourteousComputing efficiently
What is gained when is computed as (for ) rather than the "direct" (but not naive) way?

You get a smaller base (not sure if that helps, but I'll leave it to be corrected (Giggle)) ... on the other hand, introduces (additional) error. - September 3rd 2010, 06:53 AMundefined
- September 3rd 2010, 08:11 AMcourteous
This is from a chapter on IEEE-754 standard, so call and "floats". Though, at the level of 23 (or 52 for

*double precision*) bits, they're all really just integers, aren't they?(Wondering)

The textbook uses the above (questioned) fact just for showing, that even 52 bits (*double precision*) aren't good enough for IEEE and we need 64 bits (*Extended precision*). But it doesn't show*why*is better computed as . - September 3rd 2010, 09:44 AMundefined
Perhaps this will be of some use?

Info: (gmp) Normal Powering Algorithm

There might be further notes in the source code of GMP. - September 4th 2010, 06:31 AMcourteous
Couldn't help myself with GMP documentation.

Should've looked at Wikipedia first, though this paragraph is still unclear (to me):

Quote:

Moreover, reduces the exponentiation to looking up the logarithm of c, multiplying it with (possibly using the previous method*)**and looking up the antilogarithm**of the product.

**Looking up**, as in "looking up in the tables"? Is this then what makes it efficient, the fact that computer has those tables already stored?

Without this stored table, this method isn't any more efficient, because**antilogarithm***is*exponentiation, right (or is there some subtle difference (like between antiderivative and integral, I think ... (Blush)))?

* - September 4th 2010, 06:50 AMundefined
- September 4th 2010, 08:17 AMCaptainBlack
It is (or rather can be) more efficient because you are using base 2 and a binary float representation, so logs are only ever required for numbers in the range 1 to 2, and the main part of a log can be read straight out of the exponent (-ish if we ignore the normalisation/non-normalisation complication) and the same sort of tricks can be played in the reverse direction.

CB - September 4th 2010, 11:09 PMcourteous