How do you convert $\displaystyle 14in^2$ to $\displaystyle m^2$ ?

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- Sep 2nd 2010, 09:01 PMhydrideConvert in to m
How do you convert $\displaystyle 14in^2$ to $\displaystyle m^2$ ?

- Sep 2nd 2010, 09:07 PMEducated
1 inch = 0.0254 meters

1 inch * 1 inch = 0.0254 meters * 0.0254 meters

1 inch squared = 0.00064516 meters squared - Sep 2nd 2010, 09:14 PMundefined
- Sep 3rd 2010, 09:49 AMHallsofIvy
So as long as it is

**exact**, you don't mind that it is**wrong**?

1 inch is**approximately**2.54 cm, just as 1 meter is approximately .0254 meters. Both statements have exactly the same accuracy and, in fact, say exactly the same thing.

Quote:

$\displaystyle \displaystyle 14\ \text{in}^2=(14\ \text{in}^2)\left(\frac{2.54\ \text{cm}}{1\ \text{in}} \right)^2\left(\frac{1\ \text{m}}{100\ \text{cm}} \right)^2$

- Sep 3rd 2010, 10:01 AMundefined
I think maybe you have been misinformed.

The yard is defined in terms of the metre. (source) I learned it as the inch being defined in terms of centimetre which amounts to the same thing.

The metre is defined in terms of the speed of light traveling at a certain fraction of a second. (source)

The second is defined in terms of the radioactivity of the caesium 133 atom. (source)

By the way I wasn't contradicting Educated's post; I realise they are the same precision/accuracy. I mentioned that I like to use 1 inch = 2.54 cm as a general statement; for example, I would generally not use 1 mile $\displaystyle \approx$ 1.61 km but instead convert the long way. - Sep 3rd 2010, 04:44 PMHallsofIvy
I did not understand that you were referring the to so-called "international yard".