# Problem Solving School Challenge help i fail maths if not if veri soon

• May 31st 2007, 02:38 AM
Tomm_
Problem Solving School Challenge help i fail maths if not if veri soon
Tassie decides to run a competion at her chocolate factory. the prize is a years supply of her best sellers: Rockies, Delights, Nutbix and Creams. She has 4 jars, one containing Rockies and Delights, one containing Delights and Nutbix, one containing Nutbix and Creams and one containing creams only.
:The chocolates are identical in size and are wrapped in identical foil.
:The jars are lablled Rockies and Delights, Delights and Nutbix, Nutbix and Creams and Creams, but no label is on the correct jar.
:The aim of the competion is to identify the jars correctly after selecting and unwrapping as few chocolates as possible.
:No contestant sees what another contestant unwraps.

A) Emily unwraps a chocolate from the jar labelled Rockies and Delights and it is a Nutbix. From the jar labelled Delights and Nutbix she selects a cream, from the jar labbled Nutbix and Creams she selects a nutbix and from the jar labelled Creams she draws a rockie. Show how Emily can correctly relable the jars.

B) Matt unwraps one chocolate from one and jar is able to relabel that jar correctly. Make a list of nine ways he could have done this. Explain why your list is complete.

C)Juliets selection of chocolate was lucky and she won the competition. She onli had to select 2 chocolates before she was able to relabel all the jars correctly. Explain how she could have achieved this.
• May 31st 2007, 09:22 AM
Soroban
Hello, Tomm!

I think I've got it . . .

Quote:

Tassie decides to run a competion at her chocolate factory.
The prize is a years supply of her best sellers: Rockies, Delights, Nutbix and Creams.
She has 4 jars, one with R & D, one with D & N, one with N & C and one with C only.

~ The chocolates are identical in size and are wrapped in identical foil.
~ The jars are lablled: R & D, D & N, N & C, and C, but no label is on the correct jar.
~ The aim of the competion is to identify the jars correctly after selecting
. . and unwrapping as few chocolates as possible.
~ No contestant sees what another contestant unwraps.

A) Emily unwraps a chocolate from the jar labelled R & D, and it is a N.
From the jar labelled D & N she gets a C, from the jar labelled N & C, she gets a N,
and from the jar labelled C she draws a R.
Show how Emily can correctly relable the jars.

The jars look like this:

. . . $\#1\qquad\#2\qquad\#3\qquad\#4$
. . $\boxed{\begin{array}{c}R\\D\end{array}}\quad\boxed {\begin{array}{c}D\\N\end{array}}\quad\boxed{\begi n{array}{c}N\\C\end{array}}\quad\boxed{\begin{arra y}{c}C\\. \end{array}}$

She drew R from #4.
Since the only jar with an R is R&D, #4 is $R\&D$

She drew N from #3.
The only other jar with an N is D&N; #3 is $D\&N$

She drew N from #1.
The only other jar with an N is N&C; #1 is $N\&C$

This leave $C$ for jar #2.

Quote:

B) Matt unwraps one chocolate from one jar and is able to relabel it correctly.
Make a list of nine ways he could have done this.

(1) He draws D from #1.
The only other jar with D is D&N; jar #1 is $D\&N$

(2) He draws R from #2.
The only jar with an R is R&D; jar #2 is $R\&D$

(3) He draws N from #2.
The only other jar with an N is N&C; jar #2 is $N\&C$

(4) He draws D from #2.
The only other jar with a D is R&D; jar #2 is $R\&d$

(5) He draws R from #3.
The only jar with an R is R&D; jar #3 is $R\&D$

(6) He draws N from #3.
The only other jar with an N is D&N; jar #3 is $D\&N$

(7) He draws C from #3.
The only other jar with a C is C; jar#3 is $C$

(8) He draws R from #4.
The only jar with an R is R&D; jar #4 is $R\&D$

(9) He draws C from #4.
The only other jar with a C is N&C; jar #4 is $N\&C$

Quote:

C) Juliet's selection of chocolate was lucky and she won the competition.
She had to select only 2 chocolates before she was able to relabel all the jars correctly.
Explain how she could have achieved this.

She drew R from jar #4.
The only jar with an R is R&D; jar #4 is $R\&D$

She drew D from jar #1.
The only other jar with an D is D&N; jar #1 is $D\&N$

Since jar #3 is not N&C, jar #2 is $N\&C$

Finally, jar #3 is $C$