A force of (pi + 10j)

**carlasader** · May 27th 2007, 10:15 AM

i neeed to figure out the distance and the speed of the car so i need 4 and 5 that ,thank you ...thanks in advance for help !

**earboth** · May 27th 2007, 10:45 AM

Originally Posted by carlasader

i neeed to figure out the distance and the speed of the car so i need 4 and 5 that ,thank you ...thanks in advance for help !

Hello,

to #4:

You have 2 forces which can be described by vectors:
$\overrightarrow{f_1}=\left( \begin{array}{c}p \\ 10 \end{array} \right)$ and $\overrightarrow{f_2}=\left( \begin{array}{c}3 \\ 5 \end{array} \right)$

The resulting force can be described by: $\overrightarrow{f_r}=\left( \begin{array}{c}p+3 \\ 15 \end{array} \right)$

From $F = m \cdot a$ you know that $F =2 \frac{m}{s^2} \cdot 8.5 kg = 17 N = \left | \overrightarrow{f_r}\right|$

Thus you get:

$17^2 = (3+p)^2+15^2\ \ \Longleftrightarrow \ \ p^2+6p-55=0$

You'll get the solutions: $p_1=5 \text{ or } p_2=-11$

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