find the exponent A in the equation: v=(a^2)(t^A)/x Given units position L time t T velocity v L/T acceration(a) L/T^2 answer choices a.) 4 b.)3 c.)1 d.)2 ^what do i do here?
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v=(a^2)(t^A)/x $\displaystyle \frac{L}{T} = ( \frac{L}{T^2})^2(\frac{T^A}{L})$ Now simplify and find A.
(2L/T^4)(T^A/L) =T^4 /T^A A=4 correct?^
Originally Posted by gabriel (2L/T^4)(T^A/L) =T^4 /T^A A=4 correct?^ $\displaystyle \frac{L}{T} = \frac{L}{T^{(4-A)}}$ Now solve for A.
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