the question is hair grows about 29 in/day find the rate at which it grows in nm/sec

so i did this 2.54 x 10^5(<--in to nm) times 29 in = 7.366 x10 ^8

1 day = 86,400 sec

so 7.366 x 10^8 nm/ 86,400s =8.5255 x 10^3 nm/sec

^correct?

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- Aug 12th 2010, 10:52 PMgabrielok whats wrong/right about this answer?
the question is hair grows about 29 in/day find the rate at which it grows in nm/sec

so i did this 2.54 x 10^5(<--in to nm) times 29 in = 7.366 x10 ^8

1 day = 86,400 sec

so 7.366 x 10^8 nm/ 86,400s =8.5255 x 10^3 nm/sec

^correct? - Aug 12th 2010, 11:01 PMearboth
- Aug 12th 2010, 11:03 PMgabriel
i simplified it bcuz i dont know how to use the texts in this forum sorry