3. The New York Yankees scored the following number of runs over a period of 7 games. (8, 6, 7, 7, 3, 12, 10) Which one of the following statements shown below is true?
A. Mean > Mode
B. Median > Mean
C. Range = Median
D. Mode > Median
5. The following numbers represent the Math OGT scores of 8 students.(247, 253, 310, 350, 400, 460, 480, 495) The 8th student is unhappy with her score of 495 and takes an OGT prep course. She improves her score from a 495 to a 540. Which of the following statements is NOT true if the 8th student's score of 540 replaces the score of 483 in the data set?
A. The median decreases.
B. The median remains constant.
C. The range increases.
D. The median increases.
11. There is a bag of 8 marbles. There are 5 yellow and 3 red marbles. If you select 1 marble and choose another without replacing the first marble, what is the probability of selecting 1 yellow marble and 1 red marble?
A. 10/19
B. 15/16
C. 15/28
D. 1/213.
The borders of a rectangle are defined by the following lines. They are y=5; y=1; x=0; x=-3. A triangle within the rectangle is defined by the lines x=0; y=1; and y=x+4. If you throw a dart at the rectangle (and you are guaranteed to hit it), what is the probability that the dart lands in the triangle?
A. 5/8
B. 1/2
C. 3/8
D. 1
These questions are quite confusing to me, anyone know how to go about solving these? Thanx
When the largest value increases the median (a value that divides the data
into two sets of equal size) always remains the same, so A is false.
Hence B is true.
The range is the difference between the largest and smallest value, and so
increases so C is true.
We have already delt with D, which is false.
RonL
There are two ways of doing this:
The first can be yellow and the second red which has probability (5/8)*(3/7)
since there are 5 favourable outcomes from 8 (the number of marbles in the
bag) for the first, and 3 favourable outcomes from 7 (as there are now only 7
marbles in the bag) for the second.
The first can be yellow and the second red which has probability (3/8)*(5/7)
since there are 5 favourable outcomes from 8 (the number of marbles in the
bag) for the first, and 3 favourable outcomes from 7 (as there are now only 7
marbles in the bag) for the second.
So the final probability required is the sum of these:
p=(5/8)*(3/7) + (3/8)*(5/7) = 2 (3*5)/(7*8)
RonL