A stuntman on a motorcycle jumps a river which is 5.1m wide.

He lands on the edge of the far bank, which is 2.0m lower than the bank from which he takes off.

His minimum horizontal speed at take of is?

The answer = 8.0ms^-1

Could someone tell me which formula to use?

Thanks

Nevermind, just realised the equation was 's = ut + 0.5at^2' a = 9.8

(remove this thread if needed)