Hello xiukhung Originally Posted by
xiukhung a mass of 46 kg rests on an smooth inclined plane at 38 degrees to the horizontal. It is supported by a rope held horizontally. Find the tension in the rope and the reaction of the plane on the mass.
Draw a diagram showing the forces acting on the mass:
- Its weight, $\displaystyle 46g$ N, vertically down
- The tension, $\displaystyle \displaystyle T$, in the rope
- The normal reaction, $\displaystyle \displaystyle N$, between the plane and the mass
Since the mass is in equilibrium, the sum of the vertical components of these forces is zero. So
$\displaystyle N\cos 38^o = 46g$
Solve for $\displaystyle \displaystyle N$.
The sum of the horizontal components is also zero. So:
$\displaystyle T = N\sin38^o$
Solve for $\displaystyle \displaystyle T$.
Can you complete this now?
Grandad