Electrical current problem involving a step-down transformer.

I have a little problem with this multi-part question, I think I have some of the answers but other parts of the questions throw me a little bit

P1):

Power lines carry electricity at about 120,000 volts. If a power line were stepped down by a transformer to about 120, volts how many turns would there be on the secondary coil if there were 1000 turns on the primary?

Show your calculations.

A1):

There should only be one turn on the secondary since: Primary voltage/turns in primary coil=secondary voltage/turns in secondary coil. If primary voltage= 120,000, turns in primary coil=1000 and secondary voltage=120 then 120,000/1000=120/x and x=1.

P2):

If the secondary coil in part 1 is connected to a resistor with a resistance of $\displaystyle 10\Omega$, what is the current of the second coil?

Show your calculations.

A2):

By Ohm's law current equals:voltage/resistance. If voltage=120 and resistance= 10 then 120/10=12. Therefore, there are 12A of current flowing through the secondary coil.

P3):

What is the power in the secondary coil? show your calculations

A3):

Power=current*voltage. If current=12A and voltage=120 then: power=12*120=1440w=1.44Kw.

P4):

What is the current drawn by the primary coil?Show your calculations.

A4):

The question does not specify any resistor connected to the coil, therefore I will assume that the resistance on the coil is negligible so, if resistance=0 then current=0.

there is no current flowing across the primary coil.

(I'm not sure if I'm right on this one especially.)

Thank you!