Opps, sorry, I forgot the previous parts

A car C of mass 1200kg climbs a hill of length 500m at a constant speed. The hill is inclined at an angle of 6 degrees to the horizontal. The driving force exerted by C's engine has magnitude 1800N. Another car D, also of mass 1200kg, climbs the same hill with increasing speed. The speed at the bottom is 8m/s and the speed at the top is 20m/s. It is assumed that the resistance to the motion of D is constant and has magnitude 700N. The driving force exerted by D's engine is 4 times as great when D is at the top of the hill as it is when D is at the bottom. Find the ratio of the power developed by D's engine at the top of the hill to the power developed at the bottom.

Thanks in advance!!