A car dealer sold two used cars for $9999 each. On one she made a 10% profit and the other she took a 10% lost. What is the dollar amount of her overall loss over the two transactions?
Hello, Godfather!
A tricky/sneaky/challenging problem . . .
A car dealer sold two used cars for $9999 each.
On one she made a 10% profit and the other she took a 10% loss.
What is the dollar amount of her overall loss over the two transactions?
For the first car, the selling price was $9999 including a 10% profit.
That is, $9999 equals the Cost plus 10% of the Cost.
The equation is: .C + 0.10C .= .9999 . → . 1.1C = 9999 . → . C = 9090
The car cost her $9090 and she sold it for $9999.
. . She made a profit of $909.
For the second car, the selling price was $9999 including a 10% loss.
That is, $9999 is the Cost minus 10% of the Cost.
The equation is: .C - 0.10C .= .9999 . → . 0.9C = 9999 . → . C = 11,110
The car cost her $11,100 and she sold it for $9999.
. . She had a loss of $1,110.
Therefore, her overall loss is: .$1,110 - 909 .= .$201