
A Math Problem!! Help
Guys please help me solve this problem.
Solution X is 15% salt and the rest is water. Solution Y is 8% salt and the rest is water. How many litres of solution X need to be added to 5 litres of solution Y to make a solution that is 10% salt?
However, the answer is 2, but how?? Please help

1 unit of solution X contains 0.15 units of salt: 1 unit of solution Y contains 0.08 units of salt. So A units of solution X plus 5 units of solution Y contain 0.15A + 0.40 units of salt in A+5 units. If this is 10% salt then 0.15A + 0.40 = 0.10(A+5), that is, 0.15A + 0.40 = 0.10A + 0.50. Simplifying, 0.05A = 0.10, so that A = 2, as stated.

Solution X is 15% salt and the rest is water. Solution Y is 8% salt and the rest is water. How many litres of solution X need to be added to 5 litres of solution Y to make a solution that is 10% salt?
Let q = amount to add
Format for mixtures with percents:
(% * amt) + (% * amt) = (final % * TOTAL amt)
.15q + .08(5) = .10(5 + q)
.15q + .4 = .5 + .10q
.05q = 0.1